Ultimate Dice Systems

The following are dice systems taken from the book, The Ultimate Dice Book by Mike McGuire.
Click here for book publisher information.
Betting the 11/3, Betting the 12/2, Buy bet system, Come bet parley6 and 8 place method, Sands memorial.


Betting the Eleven ( or three )
  
The eleven pays 15 to 1. We know in our layout of the 36 combinations of the dice that the 11 or 3 shows up twice making it actually a 17 to 1 shot, or showing up once in 18 rolls ( mathematically speaking ). To catch the 11, we use a series of 27 bets. We start by betting $5 on the 11 and every time we lose, we add $1 up to the 27th level if necessary. Following is an illustration of how that works.

  Roll #    Bet    Cost    Pay-off    Profit 
1 $5 $5 $75 $75
2 $6 $11 $90 $85
3 $7 $18 $105 $94
4 $8 $26 $120 $102
5 $9 $35 $135 $109
6 $10 $45 $150 $115
7 $11 $56 $165 $120
8 $12 $68 $180 $124
9 $13 $81 $195 $127
10 $14 $95 $210 $129
11 $15 $110 $225 $130
12 $16 $126 $240 $130
13 $17 $143 $255 $129
14 $18 $161 $270 $127
15 $19 $180 $285 $124
16 $20 $200 $300 $120
17 $21 $221 $315 $115
18 $22 $243 $330 $109
19 $23 $266 $345 $102
20 $24 $290 $360 $94
21 $25 $315 $375 $85
22 $26 $341 $390 $75
23 $27 $368 $405 $64
24 $28 $396 $420 $52
     25       $29    $425      $435       $40   
26 $30 $455 $450 $25
27 $31 $486 $465 $10

    As you can see, the profit varies depending on where you are in the sequence. The most you can make is $130. On the other hand, if you don't catch that 11 in 27 rolls you dump $486.
    The author tried this system and won 13 out of 15 times. He decided to add a safety factor to this system.
    You would wait for 18 straight rolls without an 11, and then start your sequence of 27. This would mean that an 11 would have to go 45 rolls without appearing for you to lose $486.                                                                                         top


Betting the Twelve ( or two )
   
This method is very similar to betting the 11.
    The 12 comes up once in 36 times in the combinations as we know them. It pays 30 to 1 with the actual odds of 35 to 1. The following is the betting sequence.

  Roll #    Bet    Cost    Pay-off    Profit 
     1         $5        $5      $150       $150   
2 $6 $11 $180 $175
3 $7 $18 $210 $199
4 $8 $26 $240 $222
5 $9 $35 $270 $244
6 $10 $45 $300 $265
7 $11 $56 $330 $285
8 $12 $68 $360 $304
9 $13 $81 $390 $322
10 $14 $95 $420 $339
11 $15 $110 $450 $355
12 $16 $126 $480 $370
13 $17 $143 $510 $384
14 $18 $161 $540 $397
15 $19 $180 $570 $409
16 $20 $200 $600 $420
17 $21 $221 $630 $430
18 $22 $243 $660 $439
19 $23 $266 $690 $447
20 $24 $290 $720 $451
21 $25 $315 $750 $460
22 $26 $341 $780 $465
23 $27 $368 $810 $469
24 $28 $396 $840 $472
    25       $29       $425       $870       $474  
26 $30 $455 $900 $475
27 $31 $486 $930 $475
28 $32 $518 $960 $474
29 $33 $551 $990 $472
30 $34 $585 $1020 $469
31 $35 $620 $1050 $465
32 $36 $656 $1080 $460
33 $37 $693 $1110 $454
34 $38 $731 $1140 $447
35 $39 $770 $1170 $439
36 $40 $810 $1200 $430
37 $41 $851 $1230 $420
38 $42 $893 $1260 $409
39 $43 $936 $1290 $397
40 $44 $980 $1320 $384
41 $45 $1025 $1350 $370
42 $46 $1071 $1380 $355
43 $47 $1118 $1410 $339
44 $48 $1166 $1440 $322
45 $49 $1215 $1470 $304
46 $50 $1265 $1500 $285
47 $51 $1316 $1530 $265
48 $52 $1368 $1560 $244
    49       $53     $1421     $1590     $222  
50 $54 $1475 $1620 $199
51 $55 $1530 $1650 $175
52 $56 $1586 $1680 $150
53 $57 $1643 $1710 $124
54 $58 $1701 $1740 $97
55 $59 $1760 $1770 $69
56 $60 $1820 $1800 $40
57 $61 $1881 $1830 $10

    The author states that he won 11 of his 13 tries at this system, but he still lost money, $27. He was up at one point by $1,937 and down as much as $1,540.
    The author doesn't recommend either betting 11 or betting 12.                          top


Buy bet system
  
You can use this system to buy the 4 or the 10. With $5 as an opening bet, you'll have to find a casino with a low minimum. Otherwise adjust your bet size accordingly.
    We'll use the 4 to illustrate. Start by buying the 4 for $5. If it loses, buy the 4 again for $5. If we lose a second time, we again buy for $5. After this loss we increase our buy bet to $10. If we continue to lose we increase our subsequent bets to $15, then $25, $35, $45, and so on adding $10 to each bet after this. After we leave our first betting level of $5 and get into the larger bets, every time we win we reduce our bet by $25. If we were betting at the $45 level and we won, our next bet would be $20. If we lost that bet our next bet would be $30 (increasing $10 every time we lose). We keep going on this up $10, down $25 until we are at $0 or $5 and then the cycle begins again. Bet until your objective (a reasonable one) is met. Never quit until a cycle is completed or you are beyond your maximum allowable loss.
    The author states that he quit after 125 rolls, about an hour and twenty minutes, and was $60 ahead. He also suggests that this is a good "dinner system". You would play long enough to win enough money to pay for dinner.                            top


Come bet parley
   
We start by waiting for a point to be established. Then, we make a come bet for $25. One of three things happen. We will lose on a craps roll, in which we make a second come bet of the same amount. Secondly, we will win with a natural and parley the win for a second come bet. Thirdly, we will establish a point and take double odds. We can, of course, lose to a seven at this point or repeat our point for a win. If we lose here, we make a $25 come bet on the next roll. If we win the point, we parlay the entire amount on the next roll on come. If we establish another point here we will not take odds, but wait for the number to repeat to complete the parley.
    I now have $25 on come and a 6 is thrown for the point. I throw up another $50 for double odds. When the point is made I receive $85 profit for the $75 invested, and I parley the entire $160 on the next come. If I then get my natural, I receive a total $320-$75 (original bet), for a net of $245. If I establish another point and win I have the same profit. If I lose, I have only lost $75. If I lose here I would return to the original $25 come bet.
    When we win we go on to the next level, or a $50 come bet. The progressions are 25, 50, 75, 100, 125, moving up $25 with each win. I now have $50 on the come and I get 5 as the point. I throw up $100 in odds, and now have $150 invested. I make my point and receive $350 back ($200 in profit). Again we will parley this amount on the next come and look for another successful parley. When completing this parley we are paid $700, and move on to the $75 level. At this point, after two series we have $1020, and a net of $945.
    As I was playing there were a few questions I did address. When you complete one series of bets, do you wait for a new point or bet come on the next roll after the previous series is completed? It makes no difference. The dice don't know when you are betting and we can't outsmart them. So, we might as well bet immediately after a series is completed. Can you work more than one come bet series? Yes, but no more than two. Anything more than that is confusing. I would suggest that you only play one until you are familiar with the system.                        top


6 and 8 place method
   
You start off by betting the 6 or the 8 and stay with that number for the entire session. You make a bet in multiples of three to accommodate the 7 to 6 payoff.
    To illustrate; You bet $3 on the 6. If it wins, great. You start again with $3. If you lose, you make another place 6 bet for $9 (increasing by $6). If you lose this bet, your next bet is $15, then $21, increasing by $6 each time. Every time you win, you reduce your wager by $9. This is similar to the Buy bet system. The cycle ends when have subtracted yourself back to a bet of $3 or less. Then you would start again at $3.
    If you start with your $3 bet and lose you go to $9. Lose again, and you next bet is $15. If you would lose three more times your next bet would be $39. Now, it would be unlikely for you to lose five in a row like this because the seven shows up only one more time than the six in 36 rolls. If this were to happen, and we won with our $39 bet, we would start subtracting and our next bet would be $30.
    We only have to win two-thirds of the time to see a slight profit, or 20 wins will offset 30 losses. Anything better and our profit will grow.
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Sands Memorial
    This system is named after a player named Sands. He would wait until he thought the numbers would run. A point gets established and he place bets all of the numbers. He would continue taking down the profits on these bets until he sevened out.
    He would again wait until he thought the numbers would run. No method is given, perhaps Sands was just superstitious. At this point, he would increase the amount he spread across the numbers so he could recover his previous loss with one bet. If a seven was to rear it's ugly face, he would go on to yet another, and final level.
                                                                                                  The first level would go like this:

  4    5    6    8    9  10
$10 $10 $12 $12 $10 $10

    As long as the numbers hit, he would pull down a profit of $14 or $18 on each roll. Of course, eventually he would seven out.
                                                                                                  The second level looks like this:

  4    5    6    8    9  10
$40 $50 $60 $60 $50 $40

    At the previous level he lost $64 on his last bet. At this level, he would recover this bet and a little extra. Most people would go back to the first level after recovering their losses, but Sands would hang in there for one more roll of the dice. His reasoning for this is that at this point there was 24 ways to win, and only 6 ways to lose. That's  a 4 to 1 edge in his favor. He would, more often than not, walk away with that extra $70 or $72. After he had won that second bet, he would have the dealer remove his bets and he would move back down to the first level. If that second killer seven caught up to him he would move on to the third level.
                                                                                                   The third level looks like this:

  4    5    6    8    9    10 
$210 $270 $324 $324 $270 $210

    At this point, you have a ton of money on the table compared to what you stand to profit. A loss at the second level would cost you $364, and a win at the third level would recover that and give you an extra $14. A loss at the third level will cost you $1608.
    The author has defined this system in the following manner:
    1. Wait for two sevens within six rolls before you bet.
    2. When this condition exists; bet level one.
    3. After you seven out at level one, wait for the next point to be established and bet level two. When you win your first bet ($70 or $72) let the bets ride for one more roll. When you win this bet, wait for the next seven and then go to level one after the next point. If you lose, go to level three.
    4. At level three, one win is enough. After that win, wait for one seven and a new point, and start again at level one. If you lose here, I'm not sure what to tell you, but after all we are gambling.                                                             top


The Ultimate Dice Book
By Mike McGuire
Published by Good 'N' Lucky Publishers
PO Box 370
Henderson, Nevada 89015

Permission to use systems given by author. See page 55 of the Ultimate Dice Book.

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